(3x+4)=(2x^2+5x)/(x-2)

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Solution for (3x+4)=(2x^2+5x)/(x-2) equation: 



(3x+4)=(2x^2+5x)/(x-2)

We move all terms to the left:

(3x+4)-((2x^2+5x)/(x-2))=0



Domain of the equation: (x-2))!=0

x∈R



We get rid of parentheses

3x-((2x^2+5x)/(x-2))+4=0

We multiply all the terms by the denominator


3x*(x-2))-((2x^2+5x)+4*(x-2))=0

We multiply parentheses

3x*(x-2))-((2x^2+5x)+4x+=0

We add all the numbers together, and all the variables

4x+3x*(x-2))-((2x^2+5x)=0

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